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X^2+18X-208=0
a = 1; b = 18; c = -208;
Δ = b2-4ac
Δ = 182-4·1·(-208)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-34}{2*1}=\frac{-52}{2} =-26 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+34}{2*1}=\frac{16}{2} =8 $
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